• Question: Sodium hydroxide (NaOH) is a strong base, and ethanol (C2H5OH) is a weak acid. The reaction between NaOH and ethanol can occur, leading to deprotonation of ethanol to form the ethoxide ion (C2H5O⁻). The reaction is as follows:\\n\\nC2H5OH + NaOH -> C2H5O⁻Na⁺ + H2O\\n\\nHowever, ethanol is a relatively weak acid compared to some other compounds, and the

    Sodium hydroxide (NaOH) is a strong base, and ethanol (C2H5OH) is a weak acid. The reaction between NaOH and ethanol can occur, leading to deprotonation of ethanol to form the ethoxide ion (C2H5O⁻). The reaction is as follows:\\n\\nC2H5OH + NaOH -> C2H5O⁻Na⁺ + H2O\\n\\nHowever, ethanol is a relatively weak acid compared to some other compounds, and the extent of deprotonation is not very high under normal conditions. In practical terms, the reaction between NaOH and ethanol is not a major concern in many situations.

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